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ipc/util: drop ipc_rcu_alloc()
No callers remain for ipc_rcu_alloc(). Drop the function. [manfred@colorfullife.com: Rediff because the memset was temporarily inside ipc_rcu_free()] Link: http://lkml.kernel.org/r/20170525185107.12869-13-manfred@colorfullife.com Signed-off-by: Kees Cook <keescook@chromium.org> Signed-off-by: Manfred Spraul <manfred@colorfullife.com> Cc: Kees Cook <keescook@chromium.org> Signed-off-by: Andrew Morton <akpm@linux-foundation.org> Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
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Linus Torvalds
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52f908904e
commit
c3f6fb6fe4
@@ -112,10 +112,7 @@ int ipcperms(struct ipc_namespace *ns, struct kern_ipc_perm *ipcp, short flg);
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* Objects are reference counted, they start with reference count 1.
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* getref increases the refcount, the putref call that reduces the recount
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* to 0 schedules the rcu destruction. Caller must guarantee locking.
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*
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* struct kern_ipc_perm must be the first member in the allocated structure.
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*/
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struct kern_ipc_perm *ipc_rcu_alloc(int size);
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int ipc_rcu_getref(struct kern_ipc_perm *ptr);
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void ipc_rcu_putref(struct kern_ipc_perm *ptr,
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void (*func)(struct rcu_head *head));
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